Matematika Sekolah Menengah Pertama 1. 30°C =____F
2. 87°C =____F
3. 90°C =____F

1. 30°C =____F
2. 87°C =____F
3. 90°C =____F

Jawab:

1. 30°C = 86 °F

2. 87°C = 188,6 °F

3. 90°C = 194 °F

Penjelasan dengan langkah-langkah:

Rumus : (0 °C × 9/5) + 32 = 32 °F

(30 °C × 9/5) + 32 = 86 °F

(87 °C × 9/5) + 32 = 188,6 °F

(90 °C × 9/5) + 32 = 194 °F

Penjelasan dengan langkah-langkah:

1. = 86°F

F =( 9/5 × C) + 32

= ( 9/5 × 30 ) + 32

= 270/5 + 32/1

= 270/5 + ? /5

= 270/5 + 160/5

= 430/5

= 86°F

2. = 188,6°F

F = ( 9/5 × C ) + 32

= ( 9/5 × 87 ) + 32

= 783/5 + 32/1

= 783/5 + ? /5

= 783/5 + 160/5

= 943/5

= 188,6°F

3. = 194°F

F = ( 9/5 × C ) + 32

= ( 9/5 × 90 ) + 32

= 810/5 + 32/1

= 810/5 + ? /5

= 810/5 + 160/5

= 970/5

= 194°F

maafkan Jikalau Ada Yang Salah......

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